Solution
= Solution
By the <factor theorem>, $x-2$ divides the <polynomial>. Division gives $2x^2+7x+3=(2x+1)(x+3)$, so
$$
\boxed{2x^3+3x^2-11x-6=(x-2)(2x+1)(x+3).}
$$
Its three <polynomial roots> are $2,-1/2,-3$.
= Solution
By the <factor theorem>, $x-2$ divides the <polynomial>. Division gives $2x^2+7x+3=(2x+1)(x+3)$, so
$$
\boxed{2x^3+3x^2-11x-6=(x-2)(2x+1)(x+3).}
$$
Its three <polynomial roots> are $2,-1/2,-3$.