Solution
= Solution
Using $\sin(\pi/6)=1/2$ in the preceding <half-angle identities> gives
$$
\sin^2\frac\pi{12}=\frac{2-\sqrt3}{4}\approx\frac{2-1.732}{4}=0.067.
$$
To two decimal places the answer is \b[$0.07$].
= Solution
Using $\sin(\pi/6)=1/2$ in the preceding <half-angle identities> gives
$$
\sin^2\frac\pi{12}=\frac{2-\sqrt3}{4}\approx\frac{2-1.732}{4}=0.067.
$$
To two decimal places the answer is \b[$0.07$].