Solution
= Solution
Equating the two <polynomials> gives $x^3-3x^2+3x-1=(x-1)^3=0$. Thus the only intersection has $x=1$ and $y=4$:
$$
\boxed{(1,4).}
$$
= Solution
Equating the two <polynomials> gives $x^3-3x^2+3x-1=(x-1)^3=0$. Thus the only intersection has $x=1$ and $y=4$:
$$
\boxed{(1,4).}
$$