Solution
= Solution
Move the constant term to the left and factor the <cubic polynomial>:
$$
2x^3+9x^2-6x-5=(x-1)(2x+1)(x+5).
$$
Setting each factor to zero gives all three <polynomial roots>:
$$
\boxed{x=1,\quad-\frac12,\quad-5.}
$$
= Solution
Move the constant term to the left and factor the <cubic polynomial>:
$$
2x^3+9x^2-6x-5=(x-1)(2x+1)(x+5).
$$
Setting each factor to zero gives all three <polynomial roots>:
$$
\boxed{x=1,\quad-\frac12,\quad-5.}
$$