Solution
= Solution
Completing the squares gives the standard equation of a <circle>:
$$
\left(x+\frac12\right)^2+(y+1)^2=\frac94.
$$
Its centre is therefore
$$
\boxed{\left(-\frac12,-1\right).}
$$
= Solution
Completing the squares gives the standard equation of a <circle>:
$$
\left(x+\frac12\right)^2+(y+1)^2=\frac94.
$$
Its centre is therefore
$$
\boxed{\left(-\frac12,-1\right).}
$$