Solution
= Solution
Expand <hyperbolic sine> in <exponential functions>:
$$
e^x\sinh3x=\frac12(e^{4x}-e^{-2x}).
$$
Integrating each term gives the <indefinite integral>
$$
\boxed{\int e^x\sinh3x\,dx=\frac18e^{4x}+\frac14e^{-2x}+C.}
$$
= Solution
Expand <hyperbolic sine> in <exponential functions>:
$$
e^x\sinh3x=\frac12(e^{4x}-e^{-2x}).
$$
Integrating each term gives the <indefinite integral>
$$
\boxed{\int e^x\sinh3x\,dx=\frac18e^{4x}+\frac14e^{-2x}+C.}
$$