Solution
= Solution
There are $100$ terms in this <arithmetic series>, starting at $4$ and ending at $202$. Pairing the first and last terms, the second and penultimate terms, and so on, gives
$$
\boxed{\sum_{n=2}^{101}2n=\frac{100}{2}(4+202)=10300.}
$$
The summand in the PDF is $2n$, not $2^n$.