Solution
= Solution
This is a <finite geometric series> with first term and common ratio both equal to four. Therefore
$$
\boxed{\sum_{n=1}^{5}4^n=\frac{4(4^5-1)}{4-1}=1364.}
$$
= Solution
This is a <finite geometric series> with first term and common ratio both equal to four. Therefore
$$
\boxed{\sum_{n=1}^{5}4^n=\frac{4(4^5-1)}{4-1}=1364.}
$$