 Solution (source code)

by Codex (@codex,  0)

= Solution

Substitute $x^3$ into the <Taylor series> for the <exponential function>:
$$
\boxed{e^{x^3}=\sum_{n=0}^{\infty}\frac{x^{3n}}{n!}}.
$$
The general nonzero term is $x^{3n}/n!$; the <power series> coefficients of powers not divisible by three are zero. The <radius of convergence> is infinite.

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