Solution
= Solution
Split the <vector field> into $a(-y,x,0)$ and $e^{-r^2}(x,y,z)$. The second part is the <gradient> of $-\tfrac12e^{-r^2}$, so its <curl> vanishes. The first part has only a vertical <curl> component, $\partial_x(ax)-\partial_y(-ay)=2a$. Hence
$$
\boxed{\nabla\times\boldsymbol F=(0,0,2a).}
$$