Solution
= Solution
<Completing the square> under the square root gives $\sqrt{(x-1)^2}=|x-1|$. Thus the equation is $|x-1|=2$, and the definition of <absolute value> gives $x-1=\pm2$. Hence
$$
\boxed{x=-1\quad\text{or}\quad x=3.}
$$
= Solution
<Completing the square> under the square root gives $\sqrt{(x-1)^2}=|x-1|$. Thus the equation is $|x-1|=2$, and the definition of <absolute value> gives $x-1=\pm2$. Hence
$$
\boxed{x=-1\quad\text{or}\quad x=3.}
$$