Solution
= Solution
Use the <substitution rule> with $u=\sqrt x$, for which $du=dx/(2\sqrt x)$ on $x>0$. The <integral> becomes $\int e^u\,du$, giving the <antiderivative>
$$
\boxed{e^{\sqrt x}+C.}
$$
= Solution
Use the <substitution rule> with $u=\sqrt x$, for which $du=dx/(2\sqrt x)$ on $x>0$. The <integral> becomes $\int e^u\,du$, giving the <antiderivative>
$$
\boxed{e^{\sqrt x}+C.}
$$