Solution
= Solution
Let $N_L$ count successful lemon seeds. By <independence> it has a <binomial distribution> with five trials and success <probability> $y$. Therefore
$$
\boxed{\mathbb P(N_L=2)=\binom52y^2(1-y)^3=10y^2(1-y)^3}.
$$
= Solution
Let $N_L$ count successful lemon seeds. By <independence> it has a <binomial distribution> with five trials and success <probability> $y$. Therefore
$$
\boxed{\mathbb P(N_L=2)=\binom52y^2(1-y)^3=10y^2(1-y)^3}.
$$