Solution
= Solution
Direct multiplication, using $i^2=-1$, gives
$$
(3-2i)(4+3i)=12+9i-8i-6i^2=18+i.
$$
Thus the <real part> is $\boxed{18}$ and the <imaginary part> is $\boxed{1}$.
= Solution
Direct multiplication, using $i^2=-1$, gives
$$
(3-2i)(4+3i)=12+9i-8i-6i^2=18+i.
$$
Thus the <real part> is $\boxed{18}$ and the <imaginary part> is $\boxed{1}$.