Solution
= Solution
Multiply numerator and denominator by the <complex conjugate> $4-3i$:
$$
\frac{3-2i}{4+3i}=\frac{(3-2i)(4-3i)}{4^2+3^2}=\frac{6-17i}{25}.
$$
Thus the <real part> is $\boxed{6/25}$ and the <imaginary part> is $\boxed{-17/25}$.
= Solution
Multiply numerator and denominator by the <complex conjugate> $4-3i$:
$$
\frac{3-2i}{4+3i}=\frac{(3-2i)(4-3i)}{4^2+3^2}=\frac{6-17i}{25}.
$$
Thus the <real part> is $\boxed{6/25}$ and the <imaginary part> is $\boxed{-17/25}$.