Solution
= Solution
Using the general solution in part (a), the <initial condition> gives
$$
1=4+\frac13+C,\qquad C=-\frac{10}{3}.
$$
Therefore the solution of this <initial value problem> is
$$
\boxed{y(x)=\frac{3x}{x^4-10x+12}.}
$$
The formula is used on the <interval> containing $x=1$ where the original <ordinary differential equation> and the displayed expression are defined.