Solution
= Solution
\b[No.] Every <vector> in the <plane> can be written as
$$
(x,y,z)^T=(-2y+3z,y,z)^T=y(-2,1,0)^T+z(3,0,1)^T.
$$
The two <linearly independent vectors> in part (ii) therefore form a <vector space basis> for this <vector subspace>. Its <dimension of a vector space>[dimension] is $2$, so any three <vectors> in it have <linear dependence>.