Solution
= Solution
Applying the <quadratic formula> to the <characteristic polynomial> gives the two <eigenvalues>
$$
\boxed{\lambda=\frac{3+\sqrt5}{2}\quad\text{or}\quad\lambda=\frac{3-\sqrt5}{2}}.
$$
= Solution
Applying the <quadratic formula> to the <characteristic polynomial> gives the two <eigenvalues>
$$
\boxed{\lambda=\frac{3+\sqrt5}{2}\quad\text{or}\quad\lambda=\frac{3-\sqrt5}{2}}.
$$