Solution
= Solution
For a <skew-symmetric matrix>, $M^T=-M$. Invariance of the <determinant> under <transpose> gives
$$
\boxed{\det M=\det M^T=\det(-M)=(-1)^n\det M.}
$$
For odd $n$, $2\det M=0$, so \b[$\det M=0$] over the real or complex numbers.