Solution (source code)

= Solution

For the stated forward <Fourier transform>, the inverse has the opposite exponential sign and a factor $1/(2\pi)$:
$$
\boxed{f(t)=\frac1{2\pi}\int_{-\infty}^{\infty}\widetilde f(\omega)e^{i\omega t}\,d\omega.}
$$
This holds under the usual hypotheses for <Fourier inversion>, or in the sense of <distributions> when appropriate.