= Solution
Substituting $r_c=\hbar k_F/(e|B|)$ into $L=2jr_c$ gives
$$
B_j=\frac{2j\hbar k_F}{eL},\qquad L=10^{-6}\ \mathrm m.
$$
Using the density-derived Fermi <wave vector> gives the first three peak magnitudes
$$
\boxed{|B_1|=0.1807\ \mathrm T,\qquad |B_2|=0.3613\ \mathrm T,\qquad |B_3|=0.5420\ \mathrm T.}
$$
The equally spaced sequence follows from the number of reflected half-orbits, not from successive quantum Hall fillings. The field polarity selecting a given injector–collector orientation follows from the <Lorentz force> direction.
Back to article page
