Solution
= Solution
\b[The coolant mass flow rate is approximately $983\ \mathrm{kg\,s^{-1}}$.] All thermal <power> leaves in the steady coolant energy rise:
$$
P=W_Cc_C(T_o-T_i).
$$
With the stated constant <specific heat capacity>,
$$
\boxed{W_C=\frac{236\times10^6}
{2400(700-600)}
=983.33\ \mathrm{kg\,s^{-1}}.}
$$
The $100\,{}^\circ\mathrm C$ difference equals a $100\ \mathrm K$ difference. Thermal <power> is used directly; no electrical conversion efficiency enters.