3
= 3
{scope}
Use $x_n=nh$, $h=1/N$, and $y_n$ for the numerical approximation in the scalar <initial value problem> $y'=f(x,y)$, $y(0)=y_0$, on $[0,1]$.
= 3
{scope}
Use $x_n=nh$, $h=1/N$, and $y_n$ for the numerical approximation in the scalar <initial value problem> $y'=f(x,y)$, $y(0)=y_0$, on $[0,1]$.