Solution
= Solution
{c}
The one-minute increment has <Poisson distribution> with parameter two, independently of where that interval occurs. Hence
$$
\boxed{\mathbb P(N_{11:01}-N_{11:00}=0)=e^{-2}\approx0.1353.}
$$
= Solution
{c}
The one-minute increment has <Poisson distribution> with parameter two, independently of where that interval occurs. Hence
$$
\boxed{\mathbb P(N_{11:01}-N_{11:00}=0)=e^{-2}\approx0.1353.}
$$