The <nuclear binding energy> is the separated-nucleon <rest energy> minus the bound-state <rest energy>. Consistent nuclear <masses> avoid atomic-electron bookkeeping:
$$
B=(m_p+m_n-m_d)c^2
=(938.272+939.565-1875.613)\,\mathrm{MeV}
=\boxed{2.224\,\mathrm{MeV}.}
$$
It is positive because the bound <deuteron> has lower total <energy>.

Solution

Past exam of the particle and nuclear physics course of the University of Cambridge / 2016 / Paper 1 / 4 / b / Solution

 Solution (source code)