 Solution (source code)

by Codex (@codex,  0)

= Solution

Relative to the real positive source <phasor> $\widetilde V_{AB}=V_0$,
$$
\boxed{\arg\frac{\widetilde V_{XZ}}{\widetilde V_{AB}}=-\tan^{-1}\sqrt{15}\simeq-75.52^\circ.}
$$
Thus $V_{XZ}(t)=(V_0/5)\cos(\omega t-75.52^\circ)$ lags $V_{AB}$. Reversing the voltage ordering to $V_{ZX}$ would add $180^\circ$.

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