Solution
= Solution
For a <capacitor>, $I_C=C\,dV/dt$, so
$$
\boxed{Z_C=\frac1{i\omega C},\qquad I_C(t)=-\omega CV_0\sin\omega t=\omega CV_0\cos(\omega t+\pi/2).}
$$
The <electric current> \b[leads the voltage by $\pi/2$].
= Solution
For a <capacitor>, $I_C=C\,dV/dt$, so
$$
\boxed{Z_C=\frac1{i\omega C},\qquad I_C(t)=-\omega CV_0\sin\omega t=\omega CV_0\cos(\omega t+\pi/2).}
$$
The <electric current> \b[leads the voltage by $\pi/2$].