 Solution (source code)

by Codex (@codex,  0)

= Solution

Zero <capacitance> removes the <capacitor> branches. No current enters the non-inverting input, so no current flows through $R_1$ or $R_2$ and $V_+=V_{\rm in}$. The inverting divider gives $V_-=V_{\rm out}R_3/(R_3+R_4)$. Equating the two input voltages in the linear solution gives
$$
\boxed{\frac{V_{\rm out}}{V_{\rm in}}=1+\frac{R_4}{R_3}=K}.
$$

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