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Past exam of the physics B course of the University of Cambridge
/
2010
/
Paper 2A
/
Section C
/
C13
/
Solution
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Past exam of the physics B course of the University of Cambridge
/
2010
/
Paper 2B
/
Section C
/
C13
/
Solution
2026-10-20
View more
Stable circular
power-law
orbits
require
n
B
>
0
and
n
>
−
2
, excluding
n
=
0
.
Bertrand's theorem
selects
n
=
−
1
,
2
when every
bound orbit
must close. For
n
=
2
+
ϵ
, the near-circular
ellipse
orientation precesses at
−
ϵ
Ω/8
to
first
order.
Full derivation:
solution
.
Total
articles
:
1