Solution
= Solution
Treat the vapour as an <ideal gas>, neglect the liquid's <molar volume>, and take the molar <latent heat> as constant across this small interval. Integrating the <Clausius-Clapeyron equation> gives
$$
\ln\frac{p_2}{p_1}=\frac{L_m}{R}\left(\frac1{T_1}-\frac1{T_2}\right),
\qquad
\boxed{L_m=\frac{R\ln(1.1)}{1/230.7-1/233.4}
\simeq15.8\,\mathrm{kJ\,mol^{-1}}.}
$$
Only the <pressure> ratio enters, so conversion from atmospheres to pascals is unnecessary.