A <heat engine> operates cyclically, absorbing <heat> $Q_h$ from a hotter source, rejecting <heat> $Q_c$ to a colder sink and delivering net <work> $W=Q_h-Q_c$. Its efficiency is $\eta=W/Q_h$. The working substance returns to its original state; the reservoirs and surroundings need not.

Solution

Past exam of the physics B course of the University of Cambridge / 2014 / Paper 2 / Section C / C10 / Solution

 Solution (source code)