= Solution
A stationary person relative to the rim has <centripetal acceleration> $a\omega^2=g$. If $u$ is a signed walking <speed> relative to the rim, the inertial tangential <speed> is $a\omega+u$, so the inward normal reaction satisfies
$$
\frac Nm=\frac{(a\omega+u)^2}{a}=g+2\omega u+\frac{u^2}{a}.
$$
Consequently the support <force> per <mass>, and hence apparent weight, is \b[$4g$ for $u=+a\omega$ and zero for $u=-a\omega$]. In the latter case the walker has zero inertial <speed> and needs no centripetal support; ordinary weight-bearing contact cannot be assumed to persist without a restraint. For <artificial gravity in a rotating ring>, the <centrifugal force> and the <Coriolis force> alone are insufficient: the walker also has relative-path <centripetal acceleration> $u^2/a$. Omitting it would give the wrong apparent weights at these large walking <speeds>.
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