The <de Broglie wavelength> fixes the same <momentum> $p=h/\lambda$, but the nonrelativistic <electron> has $K=p^2/(2m_e)$:
$$
\boxed{K_e=\frac{h^2}{2m_e\lambda^2}=6.02\times10^2\,\mathrm{eV}.}
$$
Here $K_e/(m_ec^2)\simeq0.00118$, consistent with the stated nonrelativistic approximation. The <photon energy> and <electron> <kinetic energy> are not interchangeable.

Solution

Past exam of the physics course of the year 1 of the natural sciences course of the University of Cambridge / 2013 / Paper 1 / Section A / 1 / b / Solution

 Solution (source code)