Solution
= Solution
For the lander, $u/c=35/37$, so
$$
\gamma_u=\frac1{\sqrt{1-(35/37)^2}}=\frac{37}{12}.
$$
The <relativistic kinetic energy> is
$$
\boxed{K=(\gamma_u-1)mc^2=\frac{25}{12}(4\times10^5)c^2=7.49\times10^{22}\,\mathrm J.}
$$
The rest energy $mc^2$ is excluded from <kinetic energy>.