Solution
= Solution
At the initial turning point the oscillation energy is $E=Mgh_0=0.04905\,\mathrm J$. In the high-<quality factor> regime, $Q=2\pi E/\Delta E$, so the required input per period is
$$
\boxed{\Delta E\simeq\frac{2\pi}{100}(0.04905)=3.08\times10^{-3}\,\mathrm J.}
$$
This replaces the small dissipated energy each cycle, rather than supplying the entire stored energy again.