= Solution
{c}
In the open-basin <Sverdrup balance> approximation,
$$
v_{\rm int}(y)=\frac{F_0}\beta\cos(\pi y/b),\qquad
\boxed{v_{\rm int,max}\simeq5.23\,\mathrm{m\,s^{-1}},\quad\text{northward}.}
$$
The maximum is at $y=0$. Evaluating the exact finite-friction solution instead gives its largest northward <velocity> at the eastern side of the equator, about $4.96\,\mathrm{m\,s^{-1}}$. Thus the requested scale is roughly $5\,\mathrm{m\,s^{-1}}$ northward; the exact model also resolves variation across the open basin.
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