{c}

Let $d=h-g$. It vanishes outside the <null set> $E$, so part (e) proves $d$ is a <measurable function>, regardless of its values on $E$. Since the sum of two <measurable functions> is measurable, $h=g+d$ is measurable. This is the completeness of <Lebesgue measure> under changes on <null sets>.

Solution

Past exam of the probability, statistics and options I course of the University of Oxford / 2011 / D / 1 / f / Solution

 Solution (source code)