= Solution
With one parameter fitted to the grouped cells, the reference <degrees of freedom> are $10-1-1=8$. The table already gives a deviance of $8.29$ at $0.93$, so the minimized deviance is no larger than that; its direct grouped <local minimum>[minimum] is about $7.76$. Either is below the supplied critical value $15.51$. Therefore \b[do not reject the fitted grouped log-series model at level five percent]. The estimate being profiled in this test is the grouped-<likelihood> estimate described above, not the different full-data score estimate.
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