A subset $B$ of a <metric space> is <bounded> if it lies in a ball of finite radius: there exist a point $x_0$ and $R<\infty$ such that $d(x,x_0)\le R$ for every $x\in B$. Equivalently its <diameter> $\sup_{x,y\in B}d(x,y)$ is finite, with the empty set <bounded> by convention.

Solution

Past exam of the Probability, statistics and options II course of the University of Oxford / 2010 / E / E4 / a / ii / Solution

 Solution (source code)