Solution
= Solution
At $(-1,0)$ the <gradient> is $(1/2,0)^T$. The <total derivative> is therefore the <linear functional>
$$
\boxed{Df(-1,0)(h,k)=\frac h2,\qquad J_f(-1,0)=\begin{pmatrix}1/2&0\end{pmatrix}.}
$$
= Solution
At $(-1,0)$ the <gradient> is $(1/2,0)^T$. The <total derivative> is therefore the <linear functional>
$$
\boxed{Df(-1,0)(h,k)=\frac h2,\qquad J_f(-1,0)=\begin{pmatrix}1/2&0\end{pmatrix}.}
$$