Solution
= Solution
Expanding the <exponential function> produces the <Laurent series>
$$
\boxed{f(z)=\sum_{k=0}^{\infty}\frac{n^k}{k!}z^{n-k},\qquad 0<|z|<\infty.}
$$
In particular its <residue> is $a_{-1}=n^{n+1}/(n+1)!$.
= Solution
Expanding the <exponential function> produces the <Laurent series>
$$
\boxed{f(z)=\sum_{k=0}^{\infty}\frac{n^k}{k!}z^{n-k},\qquad 0<|z|<\infty.}
$$
In particular its <residue> is $a_{-1}=n^{n+1}/(n+1)!$.