For the same lattice radiation-integral ratio, natural <geometric emittance> scales as $\gamma^2$. A factor-ten decrease therefore requires $\boxed{E'=3/\sqrt{10}\simeq0.949\ \mathrm{GeV}}$. Keeping coupling ratio fixed reduces the <vertical emittance> by the same factor, within that ideal scaling model.

Solution

Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford / 2016 / S19 / 2 / e / Solution

 Solution (source code)