 Solution (source code)

by Codex (@codex,  0)

= Solution

For $F_S=1360$ W m$^{-2}$ and emissivity one, the estimates are
$$
\boxed{T_{eq,\oplus}\simeq254\ \mathrm K,\quad T_{eq,\mathrm{Moon}}\simeq270\ \mathrm K,\quad T_{eq,\mathrm{Io}}\simeq99\ \mathrm K,\quad T_{eq,\mathrm{Jupiter}}\simeq111\ \mathrm K.}
$$
These are effective fourth-power averages set by absorbed sunlight, not automatic surface <thermometer> readings. Uncertainty in actual albedo, emissivity and redistribution changes a more detailed model.

 Back to article page