= Solution
Doubling the number of identical-angle bends halves each angle. The minimum emittance scales as $\theta^3$, so it becomes $\boxed{0.240\ \mathrm{nm\,rad}}$. At unchanged <energy> and unchanged individual magnet length, the bending <radius> doubles and field halves, giving $B=0.70$ T and $\boxed{E_c\simeq4.19\ \mathrm{keV}}$.
At fixed stored current the loss per turn, proportional to $E^4\oint ds/\rho^2$, halves: twice as many equal-length bends each have one quarter of the original contribution. Total radiation power therefore halves. The <spectrum (topology)>[spectrum] softens by the factor-two critical-energy change. The characteristic high-energy vertical opening angle remains of order $1/\gamma$ at fixed <energy>, while each magnet's horizontal sweep halves. At a \i[fixed absolute] <photon energy> the normalized spectral position changes, so a claim that every <angular distribution> is identical would be too strong. Lower emittance also reduces the <electron> source size/divergence subject to the optical functions.
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