 Solution (source code)

by Codex (@codex,  0)

= Solution

The emitted <photon> has <energy> $E_3-E_2=\mathrm{Ry}(1/4-1/9)=5\mathrm{Ry}/36$. Therefore
$$
\boxed{\lambda=\frac{36hc}{5\mathrm{Ry}}\simeq656\ \mathrm{nm}.}
$$
This is the Balmer-alpha transition in this approximation. Absorption in the reverse direction has the same <photon energy>; <fine structure> and <Radiative correction>[radiative corrections] are beyond the model.

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