= Solution
For uniform <circular motion>, the transverse <Lorentz force> supplies the change in direction of <three-momentum>:
$$
e uB=\frac{pu}{r},\qquad p=eBr,\qquad
\gamma=\sqrt{1+\left(\frac{eBr}{m_ec}\right)^2}.
$$
The <magnetic rigidity> relation gives $pc=0.299792458B[\mathrm T]r[\mathrm m]\,\mathrm{GeV}=2.99792458\,\mathrm{GeV}$. Using $m_ec^2=0.511\,\mathrm{MeV}$,
$$
\boxed{\gamma\simeq5.867\times10^3,\qquad
\mathcal E=\gamma m_ec^2\simeq2.998\,\mathrm{GeV}.}
$$
The coordinate <centripetal acceleration> is $a=u^2/r$. For transverse <acceleration>, the magnitude of the <four-acceleration>, or <proper acceleration>, is $a_0=\gamma^2a$. The supplied <Larmor formula>, in its <proper acceleration> form, therefore gives
$$
P=\frac{e^2\gamma^4u^4}{6\pi\epsilon_0c^3r^2},\qquad
\mathcal T=\frac{2\pi r}{u},\qquad
\Delta\mathcal E=P\mathcal T
=\frac{e^2}{3\epsilon_0r}\gamma^4\beta^3,
\quad \beta=u/c.
$$
The emitted <power> here is also the laboratory total emitted <power>: in the instantaneous rest <inertial frame> the dipole <radiation pattern> has zero net radiated <three-momentum>, so both emitted <energy> and elapsed coordinate time gain the same <Lorentz factor> on transformation. This does not assert that a directional detector flux is invariant.
Numerically $\mathcal T\simeq1.048\times10^{-5}\,\mathrm s$, $P\simeq2.18\times10^{-10}\,\mathrm W$ per <electron>, and
$$
\boxed{\Delta\mathcal E\simeq2.29\times10^{-15}\,\mathrm J
\simeq1.43\times10^4\,\mathrm{eV}=14.3\,\mathrm{keV}\quad\text{per revolution}.}
$$
The <synchrotron>'s radiofrequency accelerating system must replace this lost <energy> to keep $r$ and <magnetic rigidity> fixed over many revolutions. The fraction lost per turn is about $4.77\times10^{-6}$, so a fixed-orbit calculation over one turn is self-consistent.<Synchrotron Radiation by Richard Fitzpatrick>[§12.22, equations (1975)–(1978): transverse radiated power and energy per revolution]{ref}
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