Solution
= Solution
The reaction Jacobian is
$$
\boxed{J=\begin{pmatrix}-b^2&-2ab\\b^2&-1+2ab\end{pmatrix}_{(3/4,1)}
=\begin{pmatrix}-1&-3/2\\1&1/2\end{pmatrix}.}
$$
Its <trace> is $-1/2$ and <determinant> is $1$, so both <eigenvalues> have negative real parts. Explicitly they are $(-1\pm i\sqrt{15})/4$. Therefore the homogeneous reaction equilibrium is a <stable focus> in the absence of diffusion.