Solution
= Solution
{c}
The <interval> $[0,1)$ is a basic <open set> contained in $[0,1]$. The remaining point $1$ is not an <interior> point, by the preceding argument. Thus
$$
\boxed{\operatorname{int}_{\mathcal T}[0,1]=[0,1).}
$$
= Solution
{c}
The <interval> $[0,1)$ is a basic <open set> contained in $[0,1]$. The remaining point $1$ is not an <interior> point, by the preceding argument. Thus
$$
\boxed{\operatorname{int}_{\mathcal T}[0,1]=[0,1).}
$$