= Solution
The <domain of a function> is fixed by its declared type, so
$$
\boxed{\operatorname{dom}f=(0,\infty).}
$$
Although the rational expression also has values at some negative arguments, they are not in the specified <domain of a function>. Part (a) of the printed question only supplies the definition used in these four subparts.<Calculus, linear algebra, discrete mathematics, logic and proof, and models of computation examination paper by the University of Oxford (2005)>[Printed p. 4, Q5(a)–(b)]{ref}
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