Solution
= Solution
For a square <matrix> $M$, an <eigenvalue>–<eigenvector> pair is a <scalar> $\lambda$ and a nonzero <vector> $v$ satisfying
$$
\boxed{Mv=\lambda v,\qquad v\ne0.}
$$
Thus the <linear map> represented by $M$ scales this particular direction by $\lambda$. The nonzero condition excludes the zero <vector>, which would otherwise satisfy the displayed equation for every <scalar>.